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约瑟夫环的循环链表实现

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#include <stdio.h><stdio.h><br>#include &lt;stdlib.h&gt;<stdlib.h></stdlib.h></stdio.h>

#define NUMBER 13 //可以通过输入确定人的个数
#define NEXT 8 //确定报数的间隔数
#define LENGTH sizeof(MEN)
#define NULL 0

struct men
{
int number;
struct men *pMen;
};

typedef struct men MEN;

/********************************************/
/* 约瑟夫环的循环链表实现*/
/********************************************/
void main()
{
MEN *pOne = NULL, *pTwo = NULL, *pHead =NULL;
int client;

/*
*创建环形链表
*/
pHead = pOne = pTwo = (MEN *)malloc(LENGTH);
pHead->number = 1;
for (client = 2; client <= NUMBER; client++)
{
pOne = (MEN *)malloc(LENGTH);
pTwo->pMen = pOne;
pOne->number = client;
pTwo = pOne;
}
pOne->pMen = pHead;
/*
*进行操作
*/
pTwo = pHead;
pOne = pTwo->pMen;
while(pOne->pMen != pTwo)
{
for(client = 0; client < NEXT - 2;client++)
{
pTwo = pOne;
pOne = pOne->pMen;
}
//if(pOne == pHead)//对于单向链表的头指针删除问题已经不存在
//pHead = pOne->pMen;
//else
pTwo->pMen = pOne->pMen;
pOne = NULL;
free(pOne);
pOne = pTwo->pMen;
pOne = pOne->pMen;
pTwo = pTwo->pMen;//保持初始状态
}
printf("%d\n", pOne->number);

}

对于每一位都有一个位权的实现:

#include <stdio.h>
#include <stdlib.h>

#define LENGTH sizeof(MEN)
#define NULL 0

struct men
{
intnumber;
intcode;
struct men *pMen;
};

typedef struct men MEN;

//////////////////////////////////////////////////////////////////////////
// 约瑟夫环的循环链表实现
//////////////////////////////////////////////////////////////////////////

void main()
{
MEN*pOne = NULL,
*pTwo = NULL,
*pHead = NULL;
intclient;
intNUMBER = 13;//设置默认的人数
intNEXT = 3; //选出的人数间隔的初始间隔数
//
//输入人数
//
printf("请输入游戏的人数:");
scanf("%d", &NUMBER);
//
//创建环形链表
//
pHead = pOne = pTwo = (MEN *)malloc(LENGTH);
if (pHead == NULL)
{
printf("头结点空间分配出错!");
return;
}
//
//初始这个链表,对头结点进行赋值
//
pHead->number = 1;
printf("请输入第1位的密码:");
scanf("%d", &pHead->code);
for (client = 2; client <= NUMBER; client++)
{
pOne = (MEN *)malloc(LENGTH);

if(pOne == NULL)
{
printf("空间分配出错!");
return;
}

pTwo->pMen = pOne;
pOne->number = client;
printf("请输入第%d位的密码:", client);
scanf("%d", &pOne->code);
pTwo = pOne;
}
pOne->pMen = pHead;

printf("\n被选出的次序:\n");
//
//进行操作
//
pTwo = pHead;
pOne = pTwo->pMen;
while(pOne->pMen != pTwo)
{
for(client = 0; client < NEXT - 2;client++)
{
pTwo = pOne;
pOne = pOne->pMen;
}
//if(pOne == pHead)//对于单向链表的头指针删除问题已经不存在
//pHead = pOne->pMen;
//else
pTwo->pMen = pOne->pMen;
//
//释放不用的结点
//
printf(" %d ", pOne->number);
NEXT = pOne->code;
pOne = NULL;
free(pOne);

pOne = pTwo->pMen;
pOne = pOne->pMen;
pTwo = pTwo->pMen;//保持初始状态
}
printf("%d", pTwo->number);
printf("\n最后留下的是:%d\n", pOne->number);
}

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